So substituting the values for the elementary symmetric polynomials that we found, we find that x, y and z are the three roots of t3 −t2 − 1 2t − 1 6 = 0 or if you prefer 6t3 − 6t2 −3t −1 = 0 In theory we could solve this using Cardano's method and directly evaluate x4 y4 z4, but the methods used above are somewhat easier
What is 2 3 x 3 4- Dec 03,21 5/x1 1/y2=2 6/x1 3/y2=1?Solution for y3=2 (x1) equation Simplifying y 3 = 2 (x 1) Reorder the terms 3 y = 2 (x 1) Reorder the terms 3 y = 2 (1 x) 3 y = (1 * 2 x * 2) 3 y = (2 2x) Solving 3 y = 2 2x Solving for variable 'y' Move all terms containing y to the left, all other terms to the right Add '3' to each side of the equation 3
What is 2 3 x 3 4のギャラリー
各画像をクリックすると、ダウンロードまたは拡大表示できます
 |  | |
 |  |  |
 |  |  |
 |  |  |
